3x^2+2x-105=0

Solution for 3x^2+2x-105=0 equation:

3x^2+2x-105=0

a = 3; b = 2; c = -105;
Δ = b2-4ac
Δ = 22-4·3·(-105)
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{79}}{2*3}=\frac{-2-4\sqrt{79}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{79}}{2*3}=\frac{-2+4\sqrt{79}}{6}
$